Populate Input Fields With Values When Option Is Selected In Php Mysql

I have a form that i would like to submit details when an option is selected from the database. The mysql database table :- USERS contains fields like [email],[age],[name]. I want

Solution 1:

Please Try this,

on your HTML page:

write this to your html page,

<script>
$(document).ready(function(){
    $('#user').on('change',function(){
        var user = $(this).val();
        $.ajax({
            url : "getUser.php",
            dataType: 'json',
            type: 'POST',
            async : false,
            data : { user : user},
            success : function(data) {
                userData = json.parse(data);
                $('#age').val(userData.age);
                $('#email').val(userData.email);
            }
        }); 
    });
});
</script>

in getUser.php:

getUser.php

<?php$link = mysqli_connect("localhost", "user", "pass","mydb");

$user = $_REQUEST['user'];    
$sql = mysqli_query($link, "SELECT age,email FROM userstable WHERE name = '".$user."' ");
$row = mysqli_fetch_array($sql);

json_encode($row);die;